(3^5x)(9^2x)=27

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Solution for (3^5x)(9^2x)=27 equation: 



(3^5x)(9^2x)=27

We move all terms to the left:

(3^5x)(9^2x)-(27)=0

We move all terms containing x to the left, all other terms to the right

3^5x9^2x=27

x=27/1

x=27

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